document.write( "Question 875340: cindy has $20,000 to invest. A part of this money is invested in bonds paying 10% annual interest. The rest of the money is invested in a savings account giving 5% annual interest. At the end of the year, she received $1,600 as an extra income. How much money did Cindy place in each investment? \n" ); document.write( "
Algebra.Com's Answer #528110 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Part I 10.00% per annum ------------- Amount invested =x \n" ); document.write( "Part II 5.00% per annum ------------ Amount invested = y \n" ); document.write( " 20000 \n" ); document.write( "Interest----- 1600.00 \n" ); document.write( " \n" ); document.write( "Part I 10.00% per annum ---x \n" ); document.write( "Part II 5.00% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 20000 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "10.00% x + 5.00% y= 1600 \n" ); document.write( "Multiply by 100 \n" ); document.write( "10 x + 5 y= 160000.00 --------2 \n" ); document.write( "Multiply (1) by -10 \n" ); document.write( "we get \n" ); document.write( "-10 x -10 y= -200000.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x -5 y= -40000 \n" ); document.write( "divide by -5 \n" ); document.write( " y = 8000 \n" ); document.write( "Part I 10.00% $ 12000 \n" ); document.write( "Part II 5.00% $ 8000 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "12000 --------- 10.00% ------- 1200.00 \n" ); document.write( "8000 ------------- 5.00% ------- 400.00 \n" ); document.write( "Total -------------------- 1600.00 \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |