document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=875141>Question 875141</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi good day how do i find the critical numbers of y=3x^3-12x^2-7 to perform the derivative test and please show me how to factor it cause i have no ideal how to do it </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #527993 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=527993\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> critical numbers of y=3x^3-12x^2-7 <BR>\n" );
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document.write( "begin by finding the y'<BR>\n" );
document.write( "y=3x^3-12x^2-7<BR>\n" );
document.write( "y'=9x^2-24x<BR>\n" );
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document.write( "Set y' to zero and solve for x to find critical points:<BR>\n" );
document.write( "0=9x^2-24x<BR>\n" );
document.write( "0=(3x)(3x-8)<BR>\n" );
document.write( "x = {0, 8/3}  (critical points)\r<BR>\n" );
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