document.write( "Question 875124: In a sample of 88 children selected randomly from on town, it is found that 8 of them suffer from asthma. Find the p-value for a test of the claim that the proportion of children with asthma is equal to 11% \n" ); document.write( "
Algebra.Com's Answer #527980 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! The alternative hypothesis is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Given Info\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p = 0.11 \n" ); document.write( "phat = 8/88 = 1/11 = 0.0909 (roughly) \n" ); document.write( "n = 88\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Test Statistic\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z = (phat - p)/(sqrt(p*(1-p)/n)) \n" ); document.write( "z = (0.0909 - 0.11)/(sqrt(0.11*(1-0.11)/88)) \n" ); document.write( "z = -0.57264221039283 \n" ); document.write( "z = -0.57\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now use a table to find the area to the left of z = -0.57\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The area to the left of z = -0.57 is 0.2843\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Double this to get 2*0.2843 = 0.5686 (remember this is a two tailed test)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The p value is 0.5686\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Side Note: this very large p value would result in failing to reject the null hypothesis for many standard significance (alpha) values. \n" ); document.write( " |