document.write( "Question 73830This question is from textbook Beginning Algebra 1A
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\n" ); document.write( "\n" ); document.write( "One day, the temperature at 2:00 A.M. was 43°F, and by 3:00 P.M. the temperature was 56°F. What was the hourly rate of temperature change?
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Algebra.Com's Answer #52798 by checkley75(3666)\"\" \"About 
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56-43=13 IS THE CHANGE IN TEMPERATURE.
\n" ); document.write( "THE DIFFERENCE IN TIME IS 3PM-2AM=13 HOURS.
\n" ); document.write( "HOURLY RATE IS 13/13=+1 DEGREE CHANGE PER HOUR.
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