document.write( "Question 73830This question is from textbook Beginning Algebra 1A
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document.write( "One day, the temperature at 2:00 A.M. was 43°F, and by 3:00 P.M. the temperature was 56°F. What was the hourly rate of temperature change? \n" );
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Algebra.Com's Answer #52798 by checkley75(3666) ![]() You can put this solution on YOUR website! 56-43=13 IS THE CHANGE IN TEMPERATURE. \n" ); document.write( "THE DIFFERENCE IN TIME IS 3PM-2AM=13 HOURS. \n" ); document.write( "HOURLY RATE IS 13/13=+1 DEGREE CHANGE PER HOUR. \n" ); document.write( " |