document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=73831>Question 73831</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0072549017/algebrahomeworkh>Beginning Algebra 1A</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Please Help\r<BR>\n" );
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document.write( "The length of a rectangle is 2 in. more than twice its width.  If the perimeter of the rectangle is 52 in., find the width of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52796 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52796\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE FORMULA FOR THE PERIMETER IS P=2L+2W WHERE L=LENGTH, W=WIDTH<BR>\n" );
document.write( "LENGTH=2W+2<BR>\n" );
document.write( "52=2(2W+2)+2W<BR>\n" );
document.write( "52=4W+4+2W<BR>\n" );
document.write( "52-4=6W<BR>\n" );
document.write( "48=6W<BR>\n" );
document.write( "W=48/6<BR>\n" );
document.write( "W=8 IN. IS THE WIDTH.<BR>\n" );
document.write( "THEN THE LENGTH IS: <BR>\n" );
document.write( "L=2*8+2<BR>\n" );
document.write( "L=16+2<BR>\n" );
document.write( "L=18 IN. IS THE LENGTH.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "52=2*8+2*18<BR>\n" );
document.write( "52=16+36<BR>\n" );
document.write( "52=52<BR>\n" );
document.write( " </SPAN>\n" );
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