document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=73833>Question 73833</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cyclist traveled at a rate of 24 mph to visit a nearby town. the cyclist averaged 18 mph on the return trip. if the round trip took 4.9 hours, find the distance to the nearby town.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52795 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52795\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> DISTANCE= RATE*TIME THUS DISTANCE/RATE=TIME OR D/R1+D/R2=TOTAL TIME. <BR>\n" );
document.write( "THE DISTANCE BEING THE ONE UNKNOWN (X).  <BR>\n" );
document.write( "X/24+X/18=4.9<BR>\n" );
document.write( "(3X+4X)/72=4.9 CROSS MULTIPLY<BR>\n" );
document.write( "3X+4X=72*4.9<BR>\n" );
document.write( "7X=352.8<BR>\n" );
document.write( "X=352.8/7<BR>\n" );
document.write( "X=50.4 MILES IS THE DISTANCE TO THE NEARBY TOWN.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "50.4/24+50.4/18=4.9<BR>\n" );
document.write( "2.1+2.8=4.9<BR>\n" );
document.write( "4.9=4.9\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );