document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=874978>Question 874978</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Quadrilateral ABCD is a parallelogram<BR>\n" );
document.write( "If AB = 2x+4y<BR>\n" );
document.write( "BC= 3x+3y<BR>\n" );
document.write( "CD= 6y+0.5x<BR>\n" );
document.write( "and AD=21<BR>\n" );
document.write( "what is 'x' and 'y'??<BR>\n" );
document.write( "I know the answer but I dont know the method.<BR>\n" );
document.write( "x=4, y=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #527881 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=527881\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we know BC = AD since they are both diagonals of the parallelogram(ABCD), therefore<BR>\n" );
document.write( "3x + 3y = 21<BR>\n" );
document.write( "x + y = 7<BR>\n" );
document.write( "now AB = CD since they are congruent sides of ABCD<BR>\n" );
document.write( "2x + 4y = 6y + 0.5x<BR>\n" );
document.write( "solve first equation for y<BR>\n" );
document.write( "y = 7 - x<BR>\n" );
document.write( "substitute for y in the second equation<BR>\n" );
document.write( "2x + 4(7-x) = 6(7-x) +0.5x<BR>\n" );
document.write( "2x + 28-4x = 42-6x +0.5x<BR>\n" );
document.write( "-2x+28 = 42 -5.5x<BR>\n" );
document.write( "3.5x = 14<BR>\n" );
document.write( "x = 4<BR>\n" );
document.write( "y = 3<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );