document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=874880>Question 874880</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular picture frame measures 8cm by 4cm. You want to triple the frames area by adding the same distance x to the length ad the width. Write and solve an equation to find the value of x. What are the new dimensions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #527821 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=527821\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Initial area of the picture frame is 32 cm^2, now we want to triple the frames area.  Therefore<BR>\n" );
document.write( "(8+x)(4+x)=96<BR>\n" );
document.write( "x^2 +12x +32=96<BR>\n" );
document.write( "x^2 +12x -64 = 0<BR>\n" );
document.write( "(x+16)(x-4)=0<BR>\n" );
document.write( "x=4 is the additional quantity to add to the dimensions of the frame<BR>\n" );
document.write( "New dimensions of the picture frame are 12 by 8\r<BR>\n" );
document.write( "<BR>\n" );
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document.write( " </SPAN>\n" );
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