document.write( "Question 874852: The area of a rectangle is 33m^2, and the length of the rectangle is 5 m less than double the width. Find the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #527780 by ewatrrr(24785)\"\" \"About 
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A = Lw = 33m^2
\n" ); document.write( " (2w-5)w = 33
\n" ); document.write( " 2w^2 - 5w - 33 = 0, w = 5.5m and L = 6m
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"2x%5E2%2B-5x%2B-33+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-5%29%5E2-4%2A2%2A-33=289\".
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\n" ); document.write( " Discriminant d=289 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--5%2B-sqrt%28+289+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-5%29%2Bsqrt%28+289+%29%29%2F2%5C2+=+5.5\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-5%29-sqrt%28+289+%29%29%2F2%5C2+=+-3\"
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\n" ); document.write( " Quadratic expression \"2x%5E2%2B-5x%2B-33\" can be factored:
\n" ); document.write( " \"2x%5E2%2B-5x%2B-33+=+2%28x-5.5%29%2A%28x--3%29\"
\n" ); document.write( " Again, the answer is: 5.5, -3.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B-5%2Ax%2B-33+%29\"
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