document.write( "Question 874855: Can a rectangle with a perimeter of 36 meters have an area of 120 sq. meters?? And how to show your work? \n" ); document.write( "
Algebra.Com's Answer #527779 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
A = Lw
\n" ); document.write( "(w-18)w = 120m^2
\n" ); document.write( " w^2 - 18w - 120 = 0
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-18x%2B-120+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-18%29%5E2-4%2A1%2A-120=804\".
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\n" ); document.write( " Discriminant d=804 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--18%2B-sqrt%28+804+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-18%29%2Bsqrt%28+804+%29%29%2F2%5C1+=+23.1774468787578\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-18%29-sqrt%28+804+%29%29%2F2%5C1+=+-5.17744687875783\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B-18x%2B-120\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-18x%2B-120+=+1%28x-23.1774468787578%29%2A%28x--5.17744687875783%29\"
\n" ); document.write( " Again, the answer is: 23.1774468787578, -5.17744687875783.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-18%2Ax%2B-120+%29\"
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