document.write( "Question 73789This question is from textbook college algebra
\n" ); document.write( ": Im stumped!!! Is there an easy way to do these? Thanks so much!\r
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\n" ); document.write( "\n" ); document.write( "Use the geometric sequence of numbers 1, 1/2, 1/4, 1/8,…to find the following:
\n" ); document.write( "a) What is r, the ratio between 2 consecutive terms?
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\n" ); document.write( "\n" ); document.write( "b) Using the formula for the sum of the first n terms of a geometric series, what is the sum of the first 10 terms? Please round your answer to 4 decimals.
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\n" ); document.write( "\n" ); document.write( "c)Using the formula for the sum of the first n terms of a geometric series, what is the sum of the first 12 terms? Please round your answer to 4 decimals.
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\n" ); document.write( "\n" ); document.write( "d) What observation can make about these sums? In particular, what whole number does it appear that the sum will always be smaller than?
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Algebra.Com's Answer #52776 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Starting with the sequence of: 1, 1/2, 1/4, 1/8,...
\n" ); document.write( "a) Find the common ratio.
\n" ); document.write( "The common ratio, r, is found by dividing any term by the preceeding term.
\n" ); document.write( "\"r+=+%281%2F2%29%2F1\"
\n" ); document.write( "\"r+=+1%2F2\"
\n" ); document.write( "or
\n" ); document.write( "\"r+=+%281%2F8%29%2F%281%2F4%29\"
\n" ); document.write( "\"r+=+%281%2F8%29%2A%284%2F1%29\"
\n" ); document.write( "\"r+=+1%2F2\"
\n" ); document.write( "The common ratio is 1/2\r
\n" ); document.write( "\n" ); document.write( "b) The partial sum of the first n terms of a geometric series is given by:
\n" ); document.write( "\"S%5Bn%5D+=+%28a%5B1%5D%281-r%5En%29%29%2F%281-r%29\" where:
\n" ); document.write( "\"n\" is the number of the term (1st, 2nd, 3rd,...)
\n" ); document.write( "\"a%5B1%5D\" is the first term.
\n" ); document.write( "\"r\" is the common ratio.
\n" ); document.write( "To find the partial sum of the first 10 terms, set \"n+=+10\", \"a%5B1%5D+=+1\", \"r+=+1%2F2\". Substitute these values into the formula for the partial sum.
\n" ); document.write( "\"S%5B10%5D+=+%281%281-%281%2F2%29%5E10%29%29%2F%281-%281%2F2%29%29\"
\n" ); document.write( "\"S%5B10%5D+=+0.9990%2F0.5\"
\n" ); document.write( "\"S%5B10%5D+=+1.9980\" To four decimal places.
\n" ); document.write( "You should be able to finish the other parts using the above as a guide.
\n" ); document.write( "If you have trouble with it, please re-post.\r
\n" ); document.write( "\n" ); document.write( "c) Find the partial sum of the first 12 terms.
\n" ); document.write( "For this part, n = 12 and we can use the same formula for the partial sum of the first n terms of a geometric sequence.
\n" ); document.write( "\"S%5B12%5D+=+%281%281-%281%2F2%29%5E12%29%29%2F%281-1%2F2%29\"
\n" ); document.write( "\"S%5B12%5D+=+0.9998%2F%281%2F2%29\"
\n" ); document.write( "\"S%5B12%5D+=+1.9995\" To four deicimal places.\r
\n" ); document.write( "\n" ); document.write( "d) My observation is that the sum approaches 2.
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