document.write( "Question 874771: The present age of father is 3 years more than 3 times the age of his son, 3 years later, father's age will be 10 years more than twice the age of his son. Determine their present ages. \n" ); document.write( "
Algebra.Com's Answer #527719 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "(3x+10) + 3 = 2(x+3) + 10
\n" ); document.write( " 3x + 13 = 2x + 16
\n" ); document.write( " x = 3, the son's age NOW. Father is 19
\n" ); document.write( "CHECKING our answer***in three years
\n" ); document.write( " \"22+=+2%2A6+%2B+10\"
\n" ); document.write( "Wish You the Best in your Studies.\r
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