document.write( "Question 874768: Tan= square root(3)/3 find sec \n" ); document.write( "

Algebra.Com's Answer #527709 by ewatrrr(24785) $\"\"$ $\"About$

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Tan (π/6) = √3/3 and Tan (7π/6) = √3/3 Interval 0 to 2π
\n" ); document.write( "sec(π/6) = 1/cos(π/6) = 1/(√3/2) = 2/√3 0r 2√3/3
\n" ); document.write( "sec(7π/6) = 1/cos(7π/6) = 1/-(√3/2) = -2/√3 0r -2√3/3
\n" ); document.write( "below (cosx, sinx) Summary
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