document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=874757>Question 874757</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 13. The sum of twice the first number, 4times the second number, and 5times the third number is 48. The difference between 5 times the first number and the second number is 7. Find the three numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #527694 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=527694\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  x + y + z = 13 (ADD (times -5)<BR>\n" );
document.write( "<u>2x + 4y + 5z = 48</u><BR>\n" );
document.write( "  -3x - y = -17  (ADD (times -1)<BR>\n" );
document.write( " <u>  5x - y = 7</u><BR>\n" );
document.write( "     8x = 24,  x = 3 and y = 8 <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15-7 ALIGN=MIDDLE  ALT=\"15-7\"   DISABLED_style= \"max-width:90%; height:auto;\" > z = 2 <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=13-3-8 ALIGN=MIDDLE  ALT=\"13-3-8\"   DISABLED_style= \"max-width:90%; height:auto;\" >  <BR>\n" );
document.write( "(3, 8, 2) the solution for this System<BR>\n" );
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