document.write( "Question 874669: How do I pair 16 people for breakfast over 15 weeks?\r
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document.write( "I can do it for 4,6 and 8 people. I can't find a pattern to move to 10 people. Here is 8:
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document.write( "Week 1 1,2 3,4 5,6 7,8
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document.write( "Week 2 1,7 2,4 3,6 5,8
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document.write( "Week 3 1,8 2,3 4,5 6,7
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document.write( "Week 4 1,4 2,6 3,8 5,7
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document.write( "Week 5 1,3 2,5 4,7 6,8
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document.write( "Week 6 1,6 2,7 4,8 5,3
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document.write( "Week 7 1,5 2,8 3,7 6,4 \n" );
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Algebra.Com's Answer #527677 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! 16C2 = 120 ways, 120/15 = 8 , 8 pairings per week for 15 weeks \n" ); document.write( "If You were to break them into 2 groups of 8 \n" ); document.write( "and then match between the two groups you could use \n" ); document.write( "something like \n" ); document.write( "(1,2) (1,3) (1,4) (1,5) (1,6) (1,7) (1,8) (2,1) \n" ); document.write( "(2,3) (2,4) (2,5) (2,6) (2,7) (2,8) (3,4) (3,5) \n" ); document.write( "(3,6) (3,7) (3,8) (4,5) (4,6) (4.7) (4,8) (5,6) \n" ); document.write( "(5,7) (5,8) (6,7) (6,8) (5',7') (5',8') (6',7') (6',8') \n" ); document.write( "remaining Other group of 8 \n" ); document.write( "(1'2') etc like above \n" ); document.write( "(2',3') etc \n" ); document.write( "(3'6') etc \n" ); document.write( "Remaining 8 weeks mix the 2 groups \n" ); document.write( "(1,1')(2,2') (3,3') (4,4') (5,5') (6.6') (7,7')(8,8') 1 Grouping \n" ); document.write( "other seven Like Above with mixed \n" ); document.write( "15 weeks - 8 groupings\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |