document.write( "Question 874589: A bank loaned out $67,000, part of it at the rate of 14% per year and the rest at a rate of 6% per year. If the interest received was $6100, how much was loaned at 14%? \n" ); document.write( "
Algebra.Com's Answer #527618 by mananth(16946)\"\" \"About 
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Part I 14.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 6.00% per annum ------------ Amount invested = y
\n" ); document.write( " 67000
\n" ); document.write( "Interest----- 6100.00
\n" ); document.write( "
\n" ); document.write( "Part I 14.00% per annum ---x
\n" ); document.write( "Part II 6.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 67000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "14.00% x + 6.00% y= 6100
\n" ); document.write( "Multiply by 100
\n" ); document.write( "14 x + 6 y= 610000.00 --------2
\n" ); document.write( "Multiply (1) by -14
\n" ); document.write( "we get
\n" ); document.write( "-14 x -14 y= -938000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x -8 y= -328000
\n" ); document.write( "divide by -8
\n" ); document.write( " y = 41000
\n" ); document.write( "Part I 14.00% $ 26000
\n" ); document.write( "Part II 6.00% $ 41000
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "26000 --------- 14.00% ------- 3640.00
\n" ); document.write( "41000 ------------- 6.00% ------- 2460.00
\n" ); document.write( "Total -------------------- 6100.00
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\n" ); document.write( "m.ananth@hotmail.ca
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