document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=73779>Question 73779</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve the equation below. I seem to get the variables mixed up. This equation is not from a textbook.\r<BR>\n" );
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document.write( " x2y – 3x – y  when x = -1 and y = 1\r<BR>\n" );
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document.write( "Thank you for your help.\r<BR>\n" );
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document.write( "LadyK </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52761 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52761\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> As I understand your problem, you are to evaluate the expression:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%5E%282%29%2Ay%29-%283%2Ax%29-y ALIGN=MIDDLE  ALT=\"%28x%5E%282%29%2Ay%29-%283%2Ax%29-y\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "when you are given that x = -1 and y = 1<BR>\n" );
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document.write( "When you substitute -1 for x and +1 for y the expression becomes:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-1%29%5E2%2A%281%29+-+3%2A%28-1%29+-+%281%29 ALIGN=MIDDLE  ALT=\"%28-1%29%5E2%2A%281%29+-+3%2A%28-1%29+-+%281%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Since <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-1%29%5E2 ALIGN=MIDDLE  ALT=\"%28-1%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > = (-1)*(-1) = 1 you can replace <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-1%29%5E2 ALIGN=MIDDLE  ALT=\"%28-1%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > by +1 to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%29%2A%281%29+-+3%2A%28-1%29+-+%281%29 ALIGN=MIDDLE  ALT=\"%281%29%2A%281%29+-+3%2A%28-1%29+-+%281%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "The first product of (1)*(1) is just +1 so substitute +1 for it to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1+-+3%2A%28-1%29+-+%281%29 ALIGN=MIDDLE  ALT=\"1+-+3%2A%28-1%29+-+%281%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Next work on the middle term of -3*(-1).  Multiplying the -1 times -3 results in +3 because<BR>\n" );
document.write( "the rule is that multiplying a negative by a negative gives you a positive.  So the -3*(-1) <BR>\n" );
document.write( "can be replaced by +3 and the expression then becomes:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1+%2B+3+-+%281%29 ALIGN=MIDDLE  ALT=\"1+%2B+3+-+%281%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "The final term is simply -1 (or if you prefer a -(+1) equals -1).  Substitute this<BR>\n" );
document.write( "to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1+%2B+3+-+1 ALIGN=MIDDLE  ALT=\"1+%2B+3+-+1\"   DISABLED_style= \"max-width:90%; height:auto;\" > which reduces to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4+-1 ALIGN=MIDDLE  ALT=\"4+-1\"   DISABLED_style= \"max-width:90%; height:auto;\" > and this further becomes just <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3 ALIGN=MIDDLE  ALT=\"3\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
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document.write( "I hope this works for you.  If I misunderstood your problem, just let me know in your response<BR>\n" );
document.write( "by providing a correction to the problem statement and I'll correct the error.  <BR>\n" );
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