document.write( "Question 874351: 24. Two taps A and B can fill a tank in 20 min and 30 min, respectively. An outlet pipe C can empty the full tank in 15 min. A, B and C are opened alternatively, each for 1 min. How long will the tank to be filled? \n" ); document.write( "
Algebra.Com's Answer #527453 by dkppathak(439)\"\" \"About 
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Two taps A and B can fill a tank in 20 min and 30 min, respectively. An outlet pipe C can empty the full tank in 15 min. A, B and C are opened alternatively, each for 1 min. How long will the tank to be filled?
\n" ); document.write( "tap A can fill the tank in 2o minutes
\n" ); document.write( "in 1 minute Tap Ait can fill tank 1/20 parts \r
\n" ); document.write( "\n" ); document.write( "Tap B can fill the tank in 30 minutes
\n" ); document.write( "in 1 minutes tap B can fill 1/30 parts
\n" ); document.write( "Tap C can empty tank in 15 minutes
\n" ); document.write( "Tap c can empty in 1 minutes 1/15 part
\n" ); document.write( "Tap A ,B C together can fill tank =1/20 +1/30-1/15 =1/60 parts
\n" ); document.write( "therefore full tank can fill up if all three taps are on together = 60 minutes
\n" ); document.write( "tank will get full if A B C are open alternatively 1 minutes = 60 X3 =180 minutes Or 3 hours
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