document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=73755>Question 73755</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many different batting orders are possible for the 9 men on a baseball team? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52745 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52745\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the permutation 9*8*7*6*5*4*3*2*1. Since there are 9 possible players for the first position, 8 for the 2nd (1 is taken off), 7 for the 3rd, etc. So you would multiply these numbers together. So there are 362,880 different possible batting orders. </SPAN>\n" );
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