document.write( "Question 874336: please help me solve this equation log3X + log3(x+2) = 1 solve for x \n" ); document.write( "

Algebra.Com's Answer #527437 by nerdybill(7384) $\"\"$ $\"About$

You can put this solution on YOUR website!
please help me solve this equation log3X + log3(x+2) = 1 solve for x
\n" ); document.write( ".
\n" ); document.write( "I'm assuming you meant log base 3:
\n" ); document.write( " $\"log%283%2CX%29+%2B+log%283%2Cx%2B2%29+=+1\"$
\n" ); document.write( " $\"log%283%2CX%28x%2B2%29%29+=+1\"$
\n" ); document.write( " $\"x%28x%2B2%29+=+3%5E1\"$
\n" ); document.write( " $\"x%5E2%2B2x+=+3\"$
\n" ); document.write( " $\"x%5E2%2B2x-3=0\"$
\n" ); document.write( " $\"%28x%2B3%29%28x-1%29=0\"$
\n" ); document.write( "x = {-3, 1}
\n" ); document.write( "Throw out the -3 solution (extraneous) leaving
\n" ); document.write( "x = 1 \n" ); document.write( "

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