document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=874322>Question 874322</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have to find the area of a rectangle cut into a half so the hypotenuse/ diagonal of the rectangle is 28ft. And the degree of one side of the diagonal is 28 so I have to use trig to find the area and I know I start off with sin(28)= o/28 but I don't know whAt to do after that!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #527435 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=527435\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sin 28 = length / diagonal\r<BR>\n" );
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document.write( "=length/28\r<BR>\n" );
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document.write( "length = 28* sin 28\r<BR>\n" );
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document.write( "width = cos 28* 28\r<BR>\n" );
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document.write( "Area = L * w\r<BR>\n" );
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document.write( "= 28*sin28 * 28* cos28\r<BR>\n" );
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document.write( "Area = 324.98 cm^2 </SPAN>\n" );
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