document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=874272>Question 874272</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If only given the measures of the sides of a trapezoid, with no area, how would you calculate the height or altitude of the trapezoid? Length of larger base is 35, length of smaller base is 19 and the sides connecting the two bases are congruent each with a measure of 17.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #527415 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=527415\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We may call it an isosceles trapezoid since the non parallel sides are congruent\r<BR>\n" );
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document.write( "A right triangle is formed when the altitude is drawn from smaller side on the  longer side\r<BR>\n" );
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document.write( "let height be h<BR>\n" );
document.write( "hypotenuse = 17<BR>\n" );
document.write( "base =?\r<BR>\n" );
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document.write( "35-19 = 16\r<BR>\n" );
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document.write( "b= 16/2 = 8\r<BR>\n" );
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document.write( "so<BR>\n" );
document.write( "8^2+h^2=17^2\r<BR>\n" );
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document.write( "17^2-8^2=h^2<BR>\n" );
document.write( "h^2=225<BR>\n" );
document.write( "h=15 units\r<BR>\n" );
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