document.write( "Question 864078: Use the following n=10 sample data to construct a 90% confidence interval of the population mean μ. Assume a simple random sample was taken the population SD is unknown, and the population is normally distributed.
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\n" ); document.write( "86 135 250 357 447 553 646 769 830 1135
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Algebra.Com's Answer #527405 by sheville151(1)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "x µ (x-µ) (x-µ)^2
\n" ); document.write( "86 520.8 -434.8 189051.04
\n" ); document.write( "135 520.8 -385.8 148841.64
\n" ); document.write( "250 520.8 -270.8 73332.64
\n" ); document.write( "357 520.8 -163.8 26830.44
\n" ); document.write( "447 520.8 -73.8 5446.44
\n" ); document.write( "553 520.8 32.2 1036.84
\n" ); document.write( "646 520.8 125.2 15675.04
\n" ); document.write( "769 520.8 248.2 61603.24
\n" ); document.write( "830 520.8 309.2 95604.64
\n" ); document.write( "1135 520.8 614.2 377241.640 Sum\r
\n" ); document.write( "\n" ); document.write( "5208 994663.600 sum/9 = V\r
\n" ); document.write( "\n" ); document.write( " 110518.178 sqrt V\r
\n" ); document.write( "\n" ); document.write( " SD 332.443\r
\n" ); document.write( "\n" ); document.write( "Degrees of Freedom = n - 1 --> 10 - 1 = 9 + 2 tailed .10 (90% interval)\r
\n" ); document.write( "\n" ); document.write( "9.10 on t value table = 1.833\r
\n" ); document.write( "\n" ); document.write( "ME = 1.833*332.4/sqrt(10) = 192.69\r
\n" ); document.write( "\n" ); document.write( "CI: 520.8 - 192.69 < μ < 520.8 + 192.69 (328, 714)
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