document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=874262>Question 874262</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A plane leaves an airport traveling at an average speed of 240 kilometers per hyour. How long will it take a second plane traveling the same route at an averege speed of 600kilometrs per hour to catch up with the first plane if it leaves 3 hours later. PLEASE SET UP AN EQUATION AND SOLVE. Thank you very much for your help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #527403 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=527403\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> When the second plane catches up the distance traveled by both is the same\r<BR>\n" );
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document.write( "first plane speed = 240 km/h<BR>\n" );
document.write( "time = x\r<BR>\n" );
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document.write( "distance = 240(x)\r<BR>\n" );
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document.write( "Second plane speed = 600 km/h<BR>\n" );
document.write( "time = (x-3)\r<BR>\n" );
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document.write( "distance = 600(x-3)\r<BR>\n" );
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document.write( "240x=600(x-3)\r<BR>\n" );
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document.write( "240x=600x-1800\r<BR>\n" );
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document.write( "360x=1800<BR>\n" );
document.write( "x=5 hours\r<BR>\n" );
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document.write( "second plane starts 3 hours later<BR>\n" );
document.write( "5-3=2 hours\r<BR>\n" );
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document.write( " </SPAN>\n" );
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