document.write( "Question 874241: The function f(t) =-5t2 + 20t + 60 models the approximate height of an object t seconds after it is launched. How many seconds does it take the object to hit the ground?
\n" ); document.write( "So that's the question and I am totally lost. Would you mind explaining? *I am reviewing out a textbook, I am trying to get help our teacher said it was fine to ask people how to do it if your not understanding. Thank you.
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Algebra.Com's Answer #527392 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Plug in f(t) = 0. We do this because f(t) represents the height and a height of 0 means you're at the ground.\r
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\n" ); document.write( "\n" ); document.write( "f(t) =-5t^2 + 20t + 60\r
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\n" ); document.write( "\n" ); document.write( "0 = -5t^2 + 20t + 60\r
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\n" ); document.write( "\n" ); document.write( "-5t^2 + 20t + 60 = 0\r
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\n" ); document.write( "\n" ); document.write( "Now solve for t using the quadratic formula\r
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Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for t:

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\n" ); document.write( " Starting with the general quadratic
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\n" ); document.write( " \"at%5E2%2Bbt%2Bc=0\"
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\n" ); document.write( " the general solution using the quadratic equation is:
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\n" ); document.write( " \"t+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"
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\n" ); document.write( " So lets solve \"-5%2At%5E2%2B20%2At%2B60=0\" ( notice \"a=-5\", \"b=20\", and \"c=60\")
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\n" ); document.write( " \"t+=+%28-20+%2B-+sqrt%28+%2820%29%5E2-4%2A-5%2A60+%29%29%2F%282%2A-5%29\" Plug in a=-5, b=20, and c=60
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\n" ); document.write( " \"t+=+%28-20+%2B-+sqrt%28+400-4%2A-5%2A60+%29%29%2F%282%2A-5%29\" Square 20 to get 400
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\n" ); document.write( " \"t+=+%28-20+%2B-+sqrt%28+400%2B1200+%29%29%2F%282%2A-5%29\" Multiply \"-4%2A60%2A-5\" to get \"1200\"
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\n" ); document.write( " \"t+=+%28-20+%2B-+sqrt%28+1600+%29%29%2F%282%2A-5%29\" Combine like terms in the radicand (everything under the square root)
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\n" ); document.write( " \"t+=+%28-20+%2B-+40%29%2F%282%2A-5%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
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\n" ); document.write( " \"t+=+%28-20+%2B-+40%29%2F-10\" Multiply 2 and -5 to get -10
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\n" ); document.write( " So now the expression breaks down into two parts
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\n" ); document.write( " \"t+=+%28-20+%2B+40%29%2F-10\" or \"t+=+%28-20+-+40%29%2F-10\"
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\n" ); document.write( " Lets look at the first part:
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\n" ); document.write( " \"x=%28-20+%2B+40%29%2F-10\"
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\n" ); document.write( " \"t=20%2F-10\" Add the terms in the numerator
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\n" ); document.write( " \"t=-2\" Divide
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\n" ); document.write( " So one answer is
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\n" ); document.write( " \"t=-2\"
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\n" ); document.write( " Now lets look at the second part:
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\n" ); document.write( " \"x=%28-20+-+40%29%2F-10\"
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\n" ); document.write( " \"t=-60%2F-10\" Subtract the terms in the numerator
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\n" ); document.write( " \"t=6\" Divide
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\n" ); document.write( " So another answer is
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\n" ); document.write( " \"t=6\"
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\n" ); document.write( " So our solutions are:
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\n" ); document.write( " \"t=-2\" or \"t=6\"
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\n" ); document.write( "\n" ); document.write( "Ignore the negative t value (negative time values make no sense)\r
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\n" ); document.write( "\n" ); document.write( "The only practical solution is \"t+=+6\"\r
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\n" ); document.write( "\n" ); document.write( "So it takes 6 seconds for the object to hit the ground.
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