document.write( "Question 874241: The function f(t) =-5t2 + 20t + 60 models the approximate height of an object t seconds after it is launched. How many seconds does it take the object to hit the ground?
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document.write( "So that's the question and I am totally lost. Would you mind explaining? *I am reviewing out a textbook, I am trying to get help our teacher said it was fine to ask people how to do it if your not understanding. Thank you. \n" );
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Algebra.Com's Answer #527392 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Plug in f(t) = 0. We do this because f(t) represents the height and a height of 0 means you're at the ground.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f(t) =-5t^2 + 20t + 60\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0 = -5t^2 + 20t + 60\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-5t^2 + 20t + 60 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now solve for t using the quadratic formula\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Ignore the negative t value (negative time values make no sense)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The only practical solution is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So it takes 6 seconds for the object to hit the ground. \n" ); document.write( " |