document.write( "Question 874164: a rectangle has a perimeter of 14 inches.A similar rectangle has a perimeter of 42 inches.The area of smaller rectangle is 10 square inches.What is the area of the larger rectangle? \n" ); document.write( "

Algebra.Com's Answer #527391 by josgarithmetic(39617) $\"\"$ $\"About$

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2x+2y=14 and 6x+6y=42, and xy=10.
\n" ); document.write( "This seems like we only need one, the smaller rectangle, and its area; until later....\r
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\n" ); document.write( "\n" ); document.write( "x+y=7 and xy=10.
\n" ); document.write( " $\"y=7-x\"$ ;
\n" ); document.write( " $\"x%287-x%29=10\"$
\n" ); document.write( " $\"-x%5E2%2B7x-10=0\"$
\n" ); document.write( " $\"x%5E2-7x%2B10=0\"$
\n" ); document.write( " $\"%28x-2%29%28x-5%29=0\"$
\n" ); document.write( "The dimensions are 2 and 5 for the smaller rectangle.\r
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\n" ); document.write( "\n" ); document.write( "The proportionality for similarity, $\"42%2F14\"$ , is found to be 3, linearly, so the larger rectangle dimensions are $\"2%2A3=6\"$ and $\"5%2A3=15\"$
\n" ); document.write( "Meaning the area of the larger rectangle is $\"highlight%286%2A15=90%29\"$ \n" ); document.write( "

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