document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=874029>Question 874029</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do I solve:<BR>\n" );
document.write( "f(x)= 4x - 3<BR>\n" );
document.write( "g(x)= x^3 + 2x<BR>\n" );
document.write( "Find (f-g)(4)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #527322 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=527322\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (f-g)(4) means f(4) - g(4). So we need to calculate f(4) and g(4) first\r<BR>\n" );
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document.write( "f(x) = 4x - 3\r<BR>\n" );
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document.write( "f(4) = 4(4) - 3\r<BR>\n" );
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document.write( "<font color=\"blue\">f(4) = 13</font>\r<BR>\n" );
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document.write( "g(x) = x^3 + 2x\r<BR>\n" );
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document.write( "g(4) = (4)^3 + 2(4)\r<BR>\n" );
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document.write( "<font color=\"purple\">g(4) = 72</font>\r<BR>\n" );
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document.write( "(f-g)(4) = f(4) - g(4)\r<BR>\n" );
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document.write( "(f-g)(4) = <font color=\"blue\">f(4)</font> - <font color=\"purple\">g(4)</font>\r<BR>\n" );
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document.write( "(f-g)(4) = <font color=\"blue\">13</font> - <font color=\"purple\">72</font>\r<BR>\n" );
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document.write( "(f-g)(4) = <font color=\"red\">-59</font>\r<BR>\n" );
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document.write( "Final Answer:\r<BR>\n" );
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document.write( "(f-g)(4) = <font color=\"red\">-59</font>\r<BR>\n" );
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