document.write( "Question 873992: Desiree is twice as old as her cousin now. In 30 years time, Desiree age will be 14 years more than 2/3 of her cousin's age.\r
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Algebra.Com's Answer #527250 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Re: TY (IF 14 was on the left side..it would need to be -14)
\n" ); document.write( "Desiree's age: 2x (cousin x)
\n" ); document.write( "in 30 years...Desiree age will be 14 years more than 2/3 of her cousin's age
\n" ); document.write( " 2x + 30 = 2/3(x+30) + 14
\n" ); document.write( " 2x + 30 = (2/3)x + (2/3)30 + 14
\n" ); document.write( " (4/3)x = 20+14-30
\n" ); document.write( " (4/3)x = 4
\n" ); document.write( " x = 3, cousin's age, Desiree is 6
\n" ); document.write( "CHECKING our answer***in 30 years
\n" ); document.write( " 36 = 2/3(33) + 14 = 22 + 14 = 36
\n" ); document.write( "Wish You the Best in your Studies.
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