document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=873997>Question 873997</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if 3x^2-2x+7=0 then (x-1/3)^2<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #527235 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=527235\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x^2-2x+7=0    <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-2%2F%283%2A2%29+=+-1%2F3 ALIGN=MIDDLE  ALT=\"-2%2F%283%2A2%29+=+-1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "3(x -1/3)^2 - 1/3 + 7 = 0<BR>\n" );
document.write( " 3(x -1/3)^2 = -20/3<BR>\n" );
document.write( " (x -1/3)^2 = -20/9<BR>\n" );
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