document.write( "Question 873944: 30% of the population of particular country favour the political party BNM. Suppose that a sample of 15 persons were randomly selected and interviewed. What is the probability that\r
\n" ); document.write( "\n" ); document.write( "1) exactly 2 of them would favour BNM?\r
\n" ); document.write( "\n" ); document.write( "2)less than 14 of them would favour BNM?\r
\n" ); document.write( "\n" ); document.write( "3) What is the variance of the random variable X, where X is the number of persons in the sample who supported BNM?\r
\n" ); document.write( "\n" ); document.write( "Suppose a random sample of 120 persons are selected. How many persons should one expect to not be supporters of BNM?\r
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Algebra.Com's Answer #527226 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "p = .30,  n = 15
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document.write( "1)P(x=2) = 15C2(.30)^2(.8)^13  0r binompdf(15, .30, 2) = .0916  0r 9.16%
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document.write( "2) P(x < 14) = 1 - P(x ≥ 14 = P(x ≤ 13) = .9999  0r 99.99%
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document.write( "3) Variance = (.30x)(.70)
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document.write( " Sample 120
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document.write( " .70(120) = non-supporters = 84 \n" );
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