document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=873960>Question 873960</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At 8.00 AM a doctor  leaves Sanford on a northbound train. Her husband,  noticing that the doctor forgot her briefcase, boards another northbound train at 10.00 AM, and travelling 18 mph  faster than the first train, the second train overtakes the first train at 4.00 PM . find the speeds of the trains,  and the distance they traveled ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #527205 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=527205\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> speed of doctor's train be x\r<BR>\n" );
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document.write( "leaves at 8.00 meets husbad  at 4.00 time = 8 hours\r<BR>\n" );
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document.write( "husband speed = (x+18)<BR>\n" );
document.write( "husband time = 6 hours\r<BR>\n" );
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document.write( "distance is same\r<BR>\n" );
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document.write( "6(x+18)=8x\r<BR>\n" );
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document.write( "6x+108=8x\r<BR>\n" );
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document.write( "2x=108<BR>\n" );
document.write( "x=54 mph\r<BR>\n" );
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document.write( "doctor's train 54 mph<BR>\n" );
document.write( "Husband's train 54+18 = 72 mph\r<BR>\n" );
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document.write( "distance = 54 *8 = 432 miles </SPAN>\n" );
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