document.write( "Question 873941: In how many ways could a committee of five people be selected from eight females and six males if the committee must have more females than males and each gender must be represented. \n" ); document.write( "
Algebra.Com's Answer #527186 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Note: I'm using the formula n C r = (n!)/(r!(n-r)!)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Break it down into cases\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4 females, 1 male: (8 C 4)*(6 C 1) = 70*6 = 420\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3 females, 2 male: (8 C 3)*(6 C 2) = 56*15 = 840\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "420+840 = 1,260\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are 1,260 ways to form the committee. \n" ); document.write( " \n" ); document.write( " |