document.write( "Question 873934: In how many ways can a student select 3 books and 4 movies to do book reports on from a potential list of 8 books and 8 movies? \n" ); document.write( "
Algebra.Com's Answer #527181 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! 8 C 3 = (8!)/(3!*(8-3)!) = 56 ways to pick 3 books\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "8 C 4 = (8!)/(4!*(8-4)!) = 70 ways to pick 4 movies\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "56*70 = 3,920 ways to do 3 books and 4 movies \n" ); document.write( " |