document.write( "Question 873825: Kira's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Kira
\n" ); document.write( "$4.85
\n" ); document.write( " per pound, and type B coffee costs
\n" ); document.write( "$5.95
\n" ); document.write( " per pound. This month's blend used twice as many pounds of type B coffee as type A, for a total cost of
\n" ); document.write( "$552.75
\n" ); document.write( ". How many pounds of type A coffee were used?
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Algebra.Com's Answer #527127 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
L = cheap coffee price - known
\n" ); document.write( "H = expensive coffee price - known
\n" ); document.write( "T = price of blend - known
\n" ); document.write( "u = pounds of cheap coffee -UNKNOWN
\n" ); document.write( "v = pounds of expensive coffee - UNKNOWN
\n" ); document.write( "v/u=2\r
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\n" ); document.write( "\n" ); document.write( "Accounting for prices,
\n" ); document.write( "\"%28L%2Au%2BH%2Av%29%2F%28u%2Bv%29=T\"
\n" ); document.write( "and as *given, \"v%2Fu=2\".\r
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\n" ); document.write( "\n" ); document.write( "The given price values may be inconvenient enough that you should solve the system of equations symbolically for u and v; and then substitute the given values of prices to determine the values of u and v.\r
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\n" ); document.write( "\n" ); document.write( "* Note, use v=2u to simplify the rational equation and first solve for u.
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