document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=873807>Question 873807</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A triangle has a perimeter of 91 inches. Find the length of the three sides if one side is 31 inches longer than the shortest side and the length of the third side is four times the shortest side. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #527117 by </B><A HREF=/tutors/aboutme.mpl?userid=harpazo><B>harpazo(655)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=harpazo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=harpazo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=527117\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The three sides:\r<BR>\n" );
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document.write( "x<BR>\n" );
document.write( "x+31<BR>\n" );
document.write( "4x\r<BR>\n" );
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document.write( "Perimeter is 91.\r<BR>\n" );
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document.write( "91 = x + x + 31 + 4x\r<BR>\n" );
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document.write( "91 = 6x + 31\r<BR>\n" );
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document.write( "91 - 31 = 6x\r<BR>\n" );
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document.write( "60 = 6x\r<BR>\n" );
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document.write( "60/6 = x\r<BR>\n" );
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document.write( "10 = x\r<BR>\n" );
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document.write( "The three sides are 10, 41 and 40.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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