document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=73672>Question 73672</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0132215179/algebrahomeworkh>introductory& intermediate algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> five gallons of 10% glucose solution is mixed wth x gallons of 40%glucose solution to obtain a 20% glucose solution. how many of the 40% solution were used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52700 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52700\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5*.10+x*.40=(5+x).20<BR>\n" );
document.write( ".5+.4x=1+.2x<BR>\n" );
document.write( ".4x-.2x=1-.5<BR>\n" );
document.write( ".2x=.5<BR>\n" );
document.write( "x=.5/.2<BR>\n" );
document.write( "x=2.5 gallons of 40% gluocose is required to make the 20% mixture.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "5*.10+2.5*.4=(5+2.5).2<BR>\n" );
document.write( ".5+1=7.5*.2<BR>\n" );
document.write( "1.5=1.5<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );