document.write( "Question 873124: I need help please!\r
\n" ); document.write( "\n" ); document.write( "Use the formula from Kepler's hire law of planetary motion, P^2=a^3, to determine P, in years, for Mercury if a=0.387 AU. \n" ); document.write( "

Algebra.Com's Answer #526995 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"P%5E2=a%5E3\"$
\n" ); document.write( " $\"P%5E2=%280.387%29%5E3\"$
\n" ); document.write( " $\"P%5E2=0.057961\"$
\n" ); document.write( " $\"P=sqrt%280.057961%29\"$
\n" ); document.write( " $\"highlight%28P=0.241%29\"$ $\"years\"$
\n" ); document.write( " \n" ); document.write( "

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