document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=873567>Question 873567</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Some 80% acid solutions is to be mixed with 35% acid solution to make 300 liters of 50% solution. How much of each acid should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #526949 by </B><A HREF=/tutors/aboutme.mpl?userid=ghostrecog><B>ghostrecog(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ghostrecog><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=526949\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution:<BR>\n" );
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document.write( "http://www.algebra.com/cgi-bin/display-illustration.mpl?tutor=ghostrecog&illustration_name=solution.bmp&size=thumbnail<BR>\n" );
document.write( "Refer from the above url, consists of table which explains the below equation.<BR>\n" );
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document.write( "Then the Equation as follows<BR>\n" );
document.write( "0.80x+0.35(300-x)=300(.50)<BR>\n" );
document.write( "0.80x+105-0.35x=150<BR>\n" );
document.write( "0.45x=45<BR>\n" );
document.write( "x=100 of 80% of acid solution<BR>\n" );
document.write( "300-x=200 of 35% of Acid solution. When mixed together we get 300 liters of solution.<BR>\n" );
document.write( " check: <BR>\n" );
document.write( "   0.80(100)  =80 liters<BR>\n" );
document.write( "   0.35(300-x)=70 liters<BR>\n" );
document.write( "   ----------------------<BR>\n" );
document.write( "   300(.50)   =150 liters </SPAN>\n" );
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