document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=873522>Question 873522</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a right triangle has a hypotenuse of 15 and one leg of length of 5. determine the length of the other leg </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #526932 by </B><A HREF=/tutors/aboutme.mpl?userid=harpazo><B>harpazo(655)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=harpazo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=harpazo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=526932\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (leg)^2 + (leg^2 = (hypotenuse)^2\r<BR>\n" );
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document.write( "Let x = the missing leg\r<BR>\n" );
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document.write( "x^2 + 5^2 = 15^2\r<BR>\n" );
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document.write( "x^2 + 25 = 225\r<BR>\n" );
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document.write( "x^2 = 225-25\r<BR>\n" );
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document.write( "x^2 = 200\r<BR>\n" );
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document.write( "Take square root of both sides.\r<BR>\n" );
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document.write( "Let sqrt = square root for short\r<BR>\n" );
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document.write( "sqrt(x^2) = sqrt(200)\r<BR>\n" );
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document.write( "x = sqrt(100) times sqrt(2)\r<BR>\n" );
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document.write( "x = 10*sqrt(2)\r<BR>\n" );
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document.write( "The missing leg has a length of 10*sqrt(2)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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