document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=873359>Question 873359</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the vertex angle of a square with sides measuring 8 units is trisected.<BR>\n" );
document.write( "Find the area of the middle triangle (has essentially four sides) and find the areas of the two right triangles.\r<BR>\n" );
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document.write( "Thanks for your help.\r<BR>\n" );
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document.write( "       </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #526822 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=526822\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the vertex angle of a square with sides measuring 8 units is trisected.<BR>\n" );
document.write( "Find the area of the middle triangle (has essentially four sides) and find the areas of the two right triangles. <BR>\n" );
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document.write( "Working with (30-60) right triangles with leg of 8 and leg x opposite 30&#730;<BR>\n" );
document.write( "tan 30&#730;=x/8<BR>\n" );
document.write( "x=8*tan30&#730;=8*1/&#8730;3=8/&#8730;3<BR>\n" );
document.write( "Area for one of the right triangles=1/2*base*height=1/2*(8/&#8730;3)*8=32&#8730;3 sq units<BR>\n" );
document.write( "Area for two of the right triangles=64&#8730;3<BR>\n" );
document.write( "Total area of square=8^2=64 sq units<BR>\n" );
document.write( "Area of middle triangle=64-64/&#8730;3=(&#8730;3*64-64)/&#8730;3=27.04 sq units </SPAN>\n" );
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