document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=873325>Question 873325</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the surface area of a cylinder with a diameter of 18 and a height of 32. Use 3.14 for p. i need help with solving this please. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #526807 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=526807\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The surface area(SA) of a cylinder is defined<BR>\n" );
document.write( "SA = 2*pi*r*h + 2*pi*r^2<BR>\n" );
document.write( "note that r is the radius (1/2 of the diameter) and h is the height<BR>\n" );
document.write( "SA = 2*(3.14)*9*32 + 2*(3.14)*9^2 <BR>\n" );
document.write( "SA = 1808.64 + 508.68 = 2317.32<BR>\n" );
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