document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=873332>Question 873332</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I am trying to find the function rule for the following table: x: 2, 4, 6  y: 1, 0, -1.  I know that it is x+2 and that the y's are decreasing by 1 each time, but I'm having a hard time finding a function rule that works for each x, y pair.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #526798 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=526798\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you have three points<BR>\n" );
document.write( "(2,1)<BR>\n" );
document.write( "(4,0)<BR>\n" );
document.write( "(6,-1)<BR>\n" );
document.write( "you have already mentioned the rise -1 (change in y) and the run +2 (change in x)<BR>\n" );
document.write( "rise over run = slope<BR>\n" );
document.write( "so the slope is -1/2<BR>\n" );
document.write( "y=-1/2x+b<BR>\n" );
document.write( "0=-1/2*4+b<BR>\n" );
document.write( "0=-2+b<BR>\n" );
document.write( "b=2<BR>\n" );
document.write( "y=-1/2x+2<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );