document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=873197>Question 873197</A>: <I><SPAN STYLE=\"word-break: break-all;\"> VERIFY sin2t-cott= -cotcos2t  this from the pre-cal trig identities section.\r<BR>\n" );
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document.write( " problem deals with the Double ANGLE Formulas. I got really confused started L--R and got stuck. tried r--L and came up with something but it doesn't look right. Any help would be greatly appreciated.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #526701 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=526701\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sin(2t)-cot(t) = -cot(t)cos(2t)<BR>\n" );
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document.write( "2sin(t)cos(t) = [-cos(t)/sin(t)][cos^2(t)-sin^2(t)]<BR>\n" );
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document.write( "2sin(t)cos(t) = [-cos(t)/sin(t)][1-sin^2(t)-sin^2(t)] <BR>\n" );
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document.write( "2sin(t)cos(t) - [cos(t)/sin(t)] = (-cos(t)/sin(t))(1-2sin^2(t))<BR>\n" );
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document.write( "Multiply each term by sin(t) to get rid of the denominators::<BR>\n" );
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document.write( "2sin^2(t)cos(t) - cos(t) = (-cos(t)(1-2sin^2(t))<BR>\n" );
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document.write( "2sin^2(t)cos(t) - cos(t) = -cos(t) + 2sin^2(t)cos(t) <BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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