document.write( "Question 873199: One alloy contains 80% gold and another alloy contains 55% gold. The two alloys are combined to make 40 grams of an alloy that is 70% gold. How many grams of the 80% alloy are used? \n" ); document.write( "
Algebra.Com's Answer #526691 by dkppathak(439)\"\" \"About 
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One alloy contains 80% gold and another alloy contains 55% gold. The two alloys are combined to make 40 grams of an alloy that is 70% gold. How many grams of the 80% alloy are used?
\n" ); document.write( "Answer
\n" ); document.write( "let x grams alloys contain 80% gold and y gram alloys contain 55% gold
\n" ); document.write( "as per conditions given X + Y =40 (1)
\n" ); document.write( "80%X +55%Y =70% of 40
\n" ); document.write( ".8x +.55 y = 28
\n" ); document.write( "80x +55y =2800 (2) by multiplying (1) by 80 and subtracting from (2)
\n" ); document.write( "80x +80Y =3200
\n" ); document.write( "-25y =-400
\n" ); document.write( "Y= 16 grams
\n" ); document.write( "X + Y =40
\n" ); document.write( "X + 16 =40
\n" ); document.write( "X= 24 grams
\n" ); document.write( "Answer
\n" ); document.write( "80% alloy contain gold =24 grams
\n" ); document.write( "55% alloy contain gold =16 grams
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