document.write( "Question 873199: One alloy contains 80% gold and another alloy contains 55% gold. The two alloys are combined to make 40 grams of an alloy that is 70% gold. How many grams of the 80% alloy are used? \n" ); document.write( "
Algebra.Com's Answer #526690 by mananth(16946)![]() ![]() You can put this solution on YOUR website! percent ---------------- quantity \n" ); document.write( "gold alloy 1 80.00% ---------------- x gms \n" ); document.write( "gold alloy 2 55.00% ------ 40 - x gms \n" ); document.write( "Mixture 70.00% ---------------- 40 \n" ); document.write( "Total 40 gms \n" ); document.write( "80.00% x + 55.00% ( 40 - x ) = 70.00% * 40 \n" ); document.write( "80 x + 55 ( 40 - x ) = 2800 \n" ); document.write( "80 x + 2200 - 55 x = 2800 \n" ); document.write( "80 x - 55 x = 2800 - -2200 \n" ); document.write( "25 x = 600 \n" ); document.write( "/ 25 \n" ); document.write( " x = 24 gms 80.00% gold alloy 1 \n" ); document.write( " 16 gms 55.00% gold alloy 2 \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |