document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=73646>Question 73646</A>: <I><SPAN STYLE=\"word-break: break-all;\"> WHat is the formula to find the 3 consecutive odd integers? We know the product of the 3 consecutive odd integers is 693. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52669 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52669\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE THREE CONSECUTIVE ODD NUMBERS ARE X, X+2, X+4. NOW WE ADD THESE THREE NUMBERS & SET THE SUM = TO 693<BR>\n" );
document.write( "X+X+2+X+4=693<BR>\n" );
document.write( "3X=693-6<BR>\n" );
document.write( "3X=682<BR>\n" );
document.write( "X=677/3<BR>\n" );
document.write( "X=229 ANSWER FOR THE FIRST ODD NUMBER<BR>\n" );
document.write( "X+2=231 FOR THE SECOND ODD NUMBER<BR>\n" );
document.write( "X+4=233 FOR THE LAST ODD NUMBER<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "229+231+233=693<BR>\n" );
document.write( "693=693 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );