document.write( "Question 73645This question is from textbook
\n" ); document.write( ": how do you solve for a system of linear equations y=2/3x-1 and y=-x+4 \n" ); document.write( "
Algebra.Com's Answer #52668 by checkley75(3666)\"\" \"About 
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SINCE Y=-X+4 THEN WE SUBSTITUTE (-X+4) FIR Y IN THE OTHER EQUATION WE GET
\n" ); document.write( "-X+4=2X/3-1
\n" ); document.write( "-X-2X/3=-1-4
\n" ); document.write( "(-3X-2X)/3=-5
\n" ); document.write( "-5X/3=-5 NOW CROSS MULTIPLY
\n" ); document.write( "-5X=-15
\n" ); document.write( "X=-15/-5
\n" ); document.write( "X=3 ANSWER. NOW SUBSTITUTE 3 FOR X & SOLVE FOR Y
\n" ); document.write( "Y=-3+4
\n" ); document.write( "Y=1 ANSWER.
\n" ); document.write( "PROOF
\n" ); document.write( "1=2/3*3-1
\n" ); document.write( "1=2-1
\n" ); document.write( "1=1
\n" ); document.write( "GRAPHS FOLLOW
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+y+=+2x%2F3+-1%2C+y+=+-x+%2B4%29+\" (graph 300x300 pixels, x from -10 to 10, y from -10 to 10, of TWO functions y = 2x/3 -1 and y = -x +4). \n" ); document.write( "
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