document.write( "Question 873162: AN OBJECT is projected vertically upward from the top of a building with an initial velocity of 144 ft./sec. its distance in feet above the ground after t secods is given by the equation s(t)=16t^2+144t+93\r
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document.write( "solve for t \n" );
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Algebra.Com's Answer #526667 by mananth(16946)![]() ![]() You can put this solution on YOUR website! I think it should be -16x^2\r \n" ); document.write( "\n" ); document.write( "At two times s= 0\r \n" ); document.write( "\n" ); document.write( "at start and when it touches the ground after a time t\r \n" ); document.write( "\n" ); document.write( "equate y=0 \n" ); document.write( "and get two values for t\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |