document.write( "Question 873015: Solve:
\n" ); document.write( "5^(x+2)=3^(x)\r
\n" ); document.write( "\n" ); document.write( "I understand that its supposed to be in log form, but I don't know what do once I get it there. Thanks so much! \n" ); document.write( "

Algebra.Com's Answer #526600 by Edwin McCravy(20067) $\"\"$ $\"About$

You can put this solution on YOUR website!

\r\n" );
document.write( "You might find it easier to use substitution of\r\n" );
document.write( "a logarithm by a letter to keep from getting\r\n" );
document.write( "bogged down in the notation.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Take logs of both sides\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Use this rule:\r\n" );
document.write( "\r\n" );
document.write( "\"The logarithm of an exponential number is the \r\n" );
document.write( "exponent times the logarithm of the base.\"\r\n" );
document.write( "\r\n" );
document.write( "(x+2)log(5) = x*log(3)\r\n" );
document.write( "\r\n" );
document.write( "Now substitute the letter A for log(5) and B for  log(3)\r\n" );
document.write( "\r\n" );
document.write( "(x+2)A = xB\r\n" );
document.write( "\r\n" );
document.write( "A(x+2) = Bx\r\n" );
document.write( "\r\n" );
document.write( "Ax+2A = Bx\r\n" );
document.write( "\r\n" );
document.write( "Ax-Bx = -2A\r\n" );
document.write( "\r\n" );
document.write( "x(A-B) = -2A\r\n" );
document.write( "\r\n" );
document.write( "x = \r\n" );
document.write( "\r\n" );
document.write( "Now replace the letter A by log(5) \r\n" );
document.write( "and the letters B by log(3) \r\n" );
document.write( "\r\n" );
document.write( "x = \r\n" );
document.write( "\r\n" );
document.write( "Then take a calculator and find x = -6.301320206\r\n" );
document.write( "\r\n" );
document.write( "Edwin

\n" ); document.write( "

\n" );