document.write( "Question 872900: A solid cone, C, is cut into two parts, X (upper) and Y (lower) by a plane parallel to the base. The lengths od the sloping edges of X is 3 cm, and Y is 2 cm. Find the ratio of:
\n" ); document.write( "a) The diameter of the base of X and C
\n" ); document.write( "b) the area of the bases of X and C
\n" ); document.write( "c) the volume of X and Y\r
\n" ); document.write( "\n" ); document.write( "I tried to use the formula for calculating thr volume of a cone: \"%281%2F3%29%2A3.14%2Ar%5E2%2Ah\" but I don't know how to apply it in this question. I also know that I have to use the formula: \"A1%2FA2+=+%28l1%2Fl2%29%5E2\" and \"A1%2FA2+=+%28l1%2Fl2%29%5E3\"
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Algebra.Com's Answer #526526 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
If two figures (on a plane), or two solid 3D shapes are similar (same shape, but maybe scaled up or down), the ratio of a certain length measures \"L\" and the ratios of surface areas \"A\" and volumes \"V\" are related.
\n" ); document.write( "Those relations are simple to understand; it's not rocket science.
\n" ); document.write( "Since scaling up (or down) is multiplying every length measurement by the same factor, that factor will be the ratio of the measures of any specific length.
\n" ); document.write( "So for any specific length measured (height, diameter, sloping edge, etc), the ratio is the scaling factor and is always the same.
\n" ); document.write( "Each surface area are the product of two lengths, so the ratios of specific surface areas will be the scaling factor, squared.
\n" ); document.write( "The volumes are the product of 3 lengths, and so their ratio is the scaling factor, cubed.
\n" ); document.write( "Those logically derived, simple relations can be expressed as mathematical formulas (equations) that can sound impressive:
\n" ); document.write( "As for areas and volumes:
\n" ); document.write( "\"A1%2FA2=%28L1%2FL2%29%5E2\" and \"V1%2FV2=%28L1%2FL2%29%5E3\" .
\n" ); document.write( "For other length, if we know length \"L\" for the two similar figured or solids,
\n" ); document.write( "the ratio of the measures of another length, \"D\" on the same figures or solids would also be the same scaling factor used for length \"L\" so
\n" ); document.write( "\"D%5B1%5D%2FD%5B2%5D=L%5B1%5D%2FL%5B2%5D\"
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\n" ); document.write( "That is what you were trying to state, isn't it?
\n" ); document.write( "You are on the right track, so I will give you the needed little nudge forward.
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\n" ); document.write( "The original cone (C) had a sloping edge measuring
\n" ); document.write( "\"L%5BC%5D=3cm%2B2cm=5cm\" .
\n" ); document.write( "That original cone (C) is similar to the upper piece (X), which has a sloping edge measuring
\n" ); document.write( "\"L%5BX%5D=3cm\" .
\n" ); document.write( "Since cone X (the upper piece) is similar to cone C (the original cone), you can use the ratios and relations above.
\n" ); document.write( "
\n" ); document.write( "a) \"D%5BX%5D%2FD%5BC%5D=L%5BX%5D%2FL%5BC%5D=highlight%283%2F5%29\"
\n" ); document.write( "
\n" ); document.write( "b) \"A%5BX%5D%2FA%5BC%5D=%28LX%2FLC%29%5E2=%283%2F5%29%5E2=highlight%289%2F15%29\"
\n" ); document.write( "
\n" ); document.write( "c) \"V%5BX%5D%2FV%5BC%5D=%28LX%2FLC%29%5E3=%283%2F5%29%5E3=27%2F125\"
\n" ); document.write( "Then,
\n" ); document.write( " \"V%5BX%5D%2FV%5BC%5D=27%2F125\"<--->\"V%5BX%5D=%2827%2F125%29V%5BC%5D\"
\n" ); document.write( "and since we know that
\n" ); document.write( "\"V%5BX%5D%2BV%5BY%5D=V%5BC%5D\"<--->\"V%5BY%5D=V%5BC%5D-V%5BX%5D\" , so
\n" ); document.write( "\"V%5BY%5D=V%5BC%5D-%2827%2F125%29V%5BC%5D\"
\n" ); document.write( "\"V%5BY%5D=%281-27%2F125%29V%5BC%5D\"
\n" ); document.write( "\"V%5BY%5D=%28125%2F125-27%2F125%29V%5BC%5D\"
\n" ); document.write( "\"V%5BY%5D=%28%28125-27%29%2F125%29V%5BC%5D\"
\n" ); document.write( "\"V%5BY%5D=%2898%2F125%29V%5BC%5D\"
\n" ); document.write( "So,
\n" ); document.write( "\"V%5BX%5D%2FV%5BY%5D=%2827%2F125%29V%5BC%5D%2F%28%2898%2F125%29V%5BC%5D%29\"--->
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